Question

8. A door of dimensions 3 m x 2m is on the wall of dimension 10 m x 10 m. Find the cost of painting the wall if rate of painting is Rs 2.50 per sq. m.​

Answer 1

Answer:

The cost of painting the wall is Rs. 235

Step-by-step explanation:

We can find the area of the door and the wall.

The door has dimensions 3m x 2m. So the area of the door is,

$Area= 3\times 2= 6 \ m^2$

Similarly, the wall has dimensions 10 m x 10 m. So the area of the wall is,

$Area= 10\times 10 =100 \ m^2$

We need to paint only the wall, So we can subtract the area of the door, as the door is on the wall. So the area of the wall that is to be painted is

$100-6 =94 \ m^2$

The cost of painting 1 square meter is Rs. 2.50. Thus the cost of painting the wall is given by,

$Cost = 2.50 \times 94 = 235$

So the cost is Rs. 235

Answer 2

Answer:

Step-by-step explanation:

Area of the wall = side × side

= (10× 10)m2

Area of the door = Length × Breadth

= (3×2) m2

Now,

Area of the wall - Area of the door

= Area to be painted

Now,

Cost of painting 1m2 = ₹2.50

Therefore, cost of painting (area to be painted) = ₹ 2.50× (area to be painted).

I hope now you can find out the answer...