Question

8.
A father leaves his money to his four children. The first received 1by3 the second received 1by6and the
third received 2by5. How much did the remaining child receive?
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Answer 1

Answer:

So here you want to look at the lowest common denominator where you have 1/3, 1/6 and 2/5. They don't have an LCD as they are, so you have to figure out what the lowest one could be. If you look at all 3 denoms, the lowest number divisible by 3, 6 and 5 is 30. So you have to convert each fraction to a fraction with 30 in the denominator.

 

So try to do that, then you can simply add the numerators together. So for example to convert 1/3 to a fraction with 30 on the bottom, multiply the top and bottom by 10:

 

1  x 10  = 10

3     10     30

Answer 2

Answer:

Step-by-step explanation:

Money the first child recieved = $\frac{1}{3}$

Money the second child recieved = $\frac{1}{6}$

Money the third child recieved = $\frac{2}{5}$

Money recieved by the three children =  $\frac{1}{3}$ + $\frac{1}{6}$ +  $\frac{2}{5}$

                                                                = $\frac{10 + 5 + 12}{30}$ = $\frac{27}{30}$ = $\frac{9}{10}$

Money recieved by the fourth child = 1 - $\frac{9}{10}$ = $\frac{1}{10}$_________ ans.

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