Question

8. A father's age is 4 times his daughter's age. Four
years back, his age was 6 times his daughter's age.
What are their current ages?​

Answer 1

old man is 6 times older than his 6 year old son. In 4 years time, the 36 year old man; will be 40 years old, and will only be 4 times older than his son; who will be 10 years old. What are their present ages?

Answer 2

Answer:

Daughter's age =10 years

Father's age=40 years

Step-by-step explanation:

Let the daughter's age=x years

Father's age is 4 times his daughter's age=4x years

four years back the daughter's age=x-4

four years back the father's age=4x-4

father's age was 6 times his daughter's age=6(x-4) =6x-24

6x-24=4x-4

6x-4x=-4+24

2x=20

x=10

daughter's age=10 years

father's age=4x=4×10=40

hence solve