Question

8. A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the
floor. Find the area of the floor that is not carpeted.
ind 5 m long​

Answer 1

$\large \sf \underbrace{ \underline{Understanding \: the \: Concept}}$

To find the area of floor which is not carpeted, we have to subtract area of Carpet from area of floor.

Given:

• Length and width of floor are 5 m and 4m respectively.
• Side of square carpet=3m

So let's start :)

$\sf Area \: of \: uncarpeted \: area=Area \: of \: floor-Area \: of \: carpet$

$\sf \large : \implies \: length \times width - (side {)}^{2}$

$\sf \large : \implies \: 5m \times 4m - (3m {)}^{2}$

$\sf \large : \implies \:{ 20m}^{2} - 9 {m}^{2}$

$\sf \large : \implies \:11{m}^{2}$

So required area=11m²

$\sf \large \underbrace{ \underline{More \: Related \: formulae}}$

$\sf \circ \: \: Area \: of \: circle=πr²$

$\sf \circ \: \: Perimeter \: of \: rectangle = l \times b$

$\sf \circ \: \: Perimeter \: of \: square=4×Side$

$\sf \circ \: \: Perimeter \: of \: circle=2πr$

$\sf \circ \: \: Area \: of \: triangle= \frac{1}{2} \times base \times height$

$\sf \circ \: \: Perimeter \: of \: triangle=Sum \: of \: all \: sides$

Answer 2

Answer:

11 m²

Step-by-step explanation:

area of floor = (lxb) sq. unit

                     = 5x4 = 20m²

area of carpet= (side)²

                       = 3² = 9m²

area of floor that is not carpeted = area of floor - area of carpet

                                                       = (20-9) m²

                                                       = 11 m²