Question

8. A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find
the area of the floor that is not carpeted.
9. Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4​

Answer 1

Solution : 8

$\bf \: \underline{Given} :$ ↴

$\sf \: Length \: of \: floor = 5 \: m$

$\sf \: Breadth \: of \: floor = 4 \: m$

$\sf \: A \: square \: carpet \: of \: sides \: 3 m \: is \: laid \: on \: the \: floor.$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: area \: of \: the \: floor \: that \: is \: not \: carpeted..$

$\bf \: \underline{ \underline{Solution }}$

$\sf \: Area \: of \: floor = length \times breadth$

$\sf \: \longrightarrow \: 5 m \times 4 m = 20 m ^{2}$

$\sf \: Now, \: Side \: of \: square \: carpet = 3 \: m$

$\sf \: Area \: of \: square \: carpet \rightarrow side \times side$

$\sf \: \longrightarrow \: 3 m \times 3 m = 9 m ^{2}$

$\sf \: Now,$

$\sf Area \:of\: floor\: that \:is \:not\: carpeted \:=$

$\underline{ \sf \: Area\: of\: floor \: - \:Area \:of \:square\: carpet}$

$\longrightarrow \sf \: 20 m^{2} \: - \: 9m^{2} = 11 m^{2}$

$\underline{ \boxed{ \pink{\sf \: So, \: area \: of \: floor \: that \: is \: not \: carpeted = 11 m^{2} }}}$

________________________________

Solution : 9

$\bf \: \underline{Correct \: question} :$ ↴

Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

$\bf \: \underline{Given} :$ ↴

Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide.

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: the \: area \: of \: the \: remaining \: part \: of \: the \: land.$

$\bf \: \underline{ \underline{Solution }}$

$\sf \: Side \: of \: square \: bed = 1 m$

$\sf \: Area \: of \: square \: bed = side \times side$

$\longrightarrow \sf\: 1 m \: \times \: 1m = 1m^{2}$

$\sf \: Area \: of \: 5 \: square \: beds = 1 \times 5 = 5 m^{2}$

$\sf \: Now,$

$\sf \: \rightarrow \: Length \: of \: land = 5 m$

$\sf \: \rightarrow \: B readth \: of \: land = 4 m$

$\sf \: Area \: of \: land = length \times B readth$

$\longrightarrow \sf\:5 m\: \times \: 4m = 20m^{2}$

$\sf \: Area \: of \: remaining \: part = Area \: of \: land - Area \: of \: 5 \: flower \: beds$

$\longrightarrow \sf\:20 m^{2}\: - \: 5m^{2} = 15m^{2}$

$\underline{ \boxed{ \pink{\sf \: So, \: area \: of \: remaining \: part \: of \: a \: land = 15 m^{2} }}}$