Question

8. A force of 10 N acts upon a body of mass 2 kg.
Calculate the acceleration.
[Ans. 5 m/s2]​

Answer 1

Answer:

Force = mass × acceleration

F=10N

m=2kg

then,

a=

m

F

=

2

10

=5m/s

2

(i) Now,

u=0

t=3sec

v=u+at=0+3×5=15m/s

(ii)Initialmomentum=mu=2×0=0

Finalmomentum=mv=2×15=30kg−m/s

Change in momentum=Final momentum - Initial momentum

=30−0=30kg−m/s

Explanation:

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Answer 2

Given that,

• Force = 10N (F)
• Mass = 2 kg (m)
• Acceleration = ? (a)

According to the Newton second law of motion,

• F = ma
• 10N = 2 kg × a
• a = 10N / 2 kg ( N = kg × m/s^2 )
• a = 10×kg×m/s^2/2kg
• a = 5m/s^2

Therefore, the acceleration of the body is 5m/s^2.

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