8. A hemispherical bowl is made of brass, 0.25 cm. thickness. The inner radius of the bow
is 5 cm. Find the ratio of outer surface area to inner surface area.
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St ep-by-step explanation:
inner radius equal 5 by 2 cm and thickness =1/4 so R =1/4+5/2=11/4cm then CSA1= 2pie 2 sq by 2pie r sq
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