Math, asked by bashsharsaud056, 7 months ago

8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is
5 cm. Find the outer curved surface area of the bowl.
analooon ninhere of​

Answers

Answered by begumnazira873
1

Answer:

express the following fraction as percentage a part 5 bye 8

Answered by GlamorousGirl
11

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\small\bold{Inner \: radius \: of \: the \: bowl \: = } 5cm

\small\bold{Thickness \: of \: the \: steel \: =} 0.25cm

\small\bold{Outer \: radius \: of \: the \: bowl \: =} 5+0.25=5.25cm

\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =} 2πr²

= 2× \large\dfrac{22}{7} × (5.25)² = 172.25 cm²

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