Question

8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is
5 cm. Find the outer curved surface area of the bowl.​

Answer 1

Inner radius of the bowl = 5cm

Thickness of the bowl = 0.25cm

External radius = 5 + 0.25 = 5.25cm

We know that

Outer curved surface area of the bowl = 2 πr2

By substituting the values

Outer curved surface area of the bowl = 2 × (22/7) × 5.252

On further calculation Outer curved surface area of the bowl = 2 × (22/7) × 27.5625

So we get

Outer curved surface area of the bowl = 173.25 cm2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.Read more on Sarthaks.com -