8. A man invests 5,600 at 14% per annum
compound interest for 2 years. Calculate :
(i) the interest for the first year.
(ii) the amount at the end of the first year.
(iii) the interest for the second year, correct to
the nearest rupee.
Answers
Answered by
13
Step-by-step explanation:
Ans1- 14%of 56000=7840
Ans2- amount for 1st yr=56000+7840=63840
Ans3- second year ci=7840+1097.6=8937.6
Answered by
32
Answer:
hey mate must note this is only Part 3 answer........
Hope it helps u
Step-by-step explanation:
For the first year:
P= Rs. 5,600, N=1 year and R=14%
We have S.I. =100PNR=1005,600×1×14= Rs. 784
And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384
Now, for the second year :
P= Rs. 6,384, N=1 year and R=14%
We have S.I.=100PNR=1006,384×1×14= Rs. 893.76
To the nearest rupee, it is Rs. 894.
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