Question

8. A man is 28.5m away from a tower. His eye level above the ground is
1.5m. The angle of elevation of the tower his eyes is 45°. Then the
height of the tower is
a) 30m b)27.5m c)28.5m
d)27m​

Answer 1

Step-by-step explanation:

$\tan45 °= p \div \: b$

height of boy is 1.5

p=perpendicular

b=base

tan 45° = P / B

1 = P/ 28.5

P = 28.5 m

AC = AB + AC

=28.5 + 1.5

= 30 m

Answer 2

Step-by-step explanation:

a) 30 m

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