Question

8: A man loses 20% of his money. After spending 25% of the remaining, he has rs.510 left with him.How much money did he originally have?
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Answer 1

Answer:

Let a man have Rs.x.Remainder money, after losses 20% of his money= x−20% of x=x−x×2010=5x−x5=4x5Remainder money, after spending 25% of hisremainder money = 4x5−25% of (4x5)= 4x5−(4x5×25100)= 4x5−x5=4x−x5=3x5According to the question,3x5=480= x=480×53 = Rs.800.

Answer 2

GiveN:

• A man loses 20% of his money. After spending 25% of the remaining, he has rs.510 left with him.

To FinD:

• How much money did he originally have?

AnsweR:

• Rs.850

Step by Step explanation:

• Let the original amount be Rs.x

$\sf \: Amount \: lost = 20\% \: of \: Rs.x \\ \\ \implies \sf \: Rs. \bigg( \frac{20}{100} \times x \bigg) = Rs. \: \frac{x}{5} \: \: \: \: \: \: \: \: \\ \\ \sf \: Remainder = Rs. \bigg(x - \frac{x}{5} \bigg) = Rs. \: \frac{4x}{5} \\ \\ \sf Expenditure = 25\% \: of \: the \: remainder \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: = 25\% \: of \: Rs. \: \frac{4x}{5} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf = Rs. \: \bigg( \frac{25}{100} \times \frac{4x}{5} \bigg) = Rs. \: \frac{x}{5} \\ \\ \sf \: Amount \: left \: \: \: = Rs. \: \bigg( \frac{4x}{5} - \frac{x}{5} \bigg) = Rs. \: \frac{3x}{5}$

• As Per Given Question,

$\\ \\ \sf \: Rs. \: \frac{3x}{5} = Rs. \: 510 \\ \\ \implies \sf \: \: \: \: \: \: \: \: \: \: \frac{3x}{5} = 510 \\ \\ \sf \implies \: \: \: \: \: \: x = \frac{510 \times5 }{3} \\ \\ \: \: \: \: \: = \: \: \: \: \: \: \: \: \: \: \: \: \: \ { \boxed{\bf{\pink {\: Rs. \: 850}}}}$

• Hence the man had Rs. 850