Math, asked by supritigupta13, 4 months ago

8.
A man's age is 20 years more than his son. Six years hence, father's age will be three times the
age of his son. Find the present age of the son.
be ten years less than twice of his presentare​

Answers

Answered by kitty7252
0

Answer:

1

5

A father's present age is 6 times his son's present age.Thirty years hence the father's age will be ten years less than twice the son's age.After how many years will the son's age be half of the father's present age?

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Answered June 24, 2020

Let present age of son be x

Then, Present age of father = 6x ( Acc. To Question )

30 yrs hence ,

Father's age = 6x + 30

Son's age = x + 30

According to Question ,

6x + 30 = 2 (x + 30) - 10

By solving the equation , we get

x = 5

Present age of son = 5 yrs

Present age of father = 6 × 5 = 30 yrs

Half of the father’s age = 30/2 = 15 yrs

This means after 15 – 5 = 10 yrs the son's age will be half of the father's present age

Answered by HruthpoorvakKS
0

Answer:

his son's present age is

Step-by-step explanation:

10years

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