8) a man sells two buffaloes for rs. 7,820 each. on one he gains 15% and on the other, he loses 15%. his total gain or loss in the transaction is
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The man loses ₹360 .
Step-by-step explanation:
- Let the cost price of the 1st Buffalo be ₹x.
selling price = ₹7820
He has gain 15%.
hence, S.P.=C.P.+ profit
so, 7820= x+ 15% of x
or, x+ 15x/100= 7820
115x/100 = 7820
x = 7820×100/115 = 6800
Hence, the Cost Price of the first Buffalo is ₹6800
- Let the cost price of the 2nd Buffalo be ₹y.
- selling price = ₹7820
- He loses 15%.
- hence, S.P.=C.P. - loss
7820= y - 15% of y
or, y - 15y/100 = 7820
85y/100 = 7820
y = 7820×100/85 =₹ 9200
- Total cost of two Buffaloes is (6800+9200)=₹16000
- Total selling price of two Buffaloes is 7820+2 = 15640
- Hence, total loss = 16000-15640=360
so, total lose of thar person in the transaction is ₹ 360.
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