Question

8. A man throws a ball to maximum horizontal
distance of 80m.Calculate the maximumheight
reached.​

Answer 1

The maximum horizontal range,

$\displaystyle\longrightarrow\sf {R_{max}=\dfrac {u^2}{g}}$

And it is attained at $\displaystyle\sf {\theta=45^{\circ}.}$

Then, the maximum height,

$\displaystyle\longrightarrow\sf {H=\dfrac {u^2\sin^2\theta}{2g}}$

$\displaystyle\longrightarrow\sf {H=\dfrac {u^2}{g}\cdot\dfrac{\sin^245^{\circ}}{2}}$

$\displaystyle\longrightarrow\sf {H=R_{max}\cdot\dfrac{\left (\dfrac {1}{2}\right)}{2}}$

$\displaystyle\longrightarrow\sf {H=\dfrac {R_{max}}{4}}$

Therefore,

$\displaystyle\longrightarrow\sf {H=\dfrac {80\ m}{4}}$

$\displaystyle\longrightarrow\sf {\underline {\underline {H=20\ m}}}$

Answer 2

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