Question

8. A man walks for x hours at a speed of (x+1) km/h and cycles for (x - 1) hours at a speed of (2x + 5) km/h. If the total distance travelled is 90 km, find x.

Answer 1

We know that
$v = \frac{d}{t}$
We can write it as
$d = v \times t$
Therefore
(x+1)*x+(2x+5)*(x-1)=Total distance
$3x^{2} + 4x - 5 = 90$
$3 {x}^{2} + 4x - 95 = 0$
On solving we get
x=5.

Hop you liked it.

Answer 2

Answer:

We know that

v =

$\frac{d}{t}$

We can write it as

d =

$v \times t$

Therefore

(x+1)*x+(2x+5)*(x-1)=Total distance

3x^{2} + 4x - 5 = 90

3 {x}^{2} + 4x - 95 = 0

On solving we get

x=5.

Hope it helps you