Physics, asked by Annmarian, 7 months ago

8. A parallel plate capacitor has plate area A and plate separation 2d. Two different dielectric

plates each of area A and thickness d are inserted as shown. The dielectric constants are K and

2K. A constant potential difference of 3V is applied between the plates of the capacitor. The

ratio of the energies stored in the upper and lower dielectric plates is ​

Answers

Answered by shambhavi1634
0

Answer:

A parallel plate capacitor of area A and separation d is charged to potential difference V and removed from the changing source. A dielectric slab of constant K =2, thickness d and are area A2 is inserted, as shown in the figure.

Explanation:

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Answered by Anonymous
0

\huge\mathrm{Answer}

A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the whole space between the plates ....

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