8. A particle experiences a constant acceleration for 20 s starting from rest. If it travels a distance S1 in the first 10 s and a distance S2 in the next 10 seconds, then what is the relation between S1 and S2
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let constant acc= a
initial velocity =u
distance in ist 10 sec= >s1 = u*10+½10t²..........(1)
dist. in ist 20 sec = >S= u *20+½20t²........(2)
dist. in last 10 sec s2= S -s1. from (1) &(2)= (20u+10t²) -(10u+5t²)= 10u+5t²
S2=s1
S2:S1
1:1 ans
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initial velocity =u
distance in ist 10 sec= >s1 = u*10+½10t²..........(1)
dist. in ist 20 sec = >S= u *20+½20t²........(2)
dist. in last 10 sec s2= S -s1. from (1) &(2)= (20u+10t²) -(10u+5t²)= 10u+5t²
S2=s1
S2:S1
1:1 ans
hope u got it. plz mark as brain liest
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