Question

8. A particle starts to move in a straight line from
a point with velocity 10 m s' and acceleration
- 20 ms? Find the position and velocity of the
particle at (i) t = 5s, (ii) t' = 10 s.​

Answer 1

Answer:

Displacement at t=5s is

S=ut+

2

1

at

2

=10×5+

2

1

×(−2.0)×(5)

2

=50−25=25m

i.e., after 5s, the particle will be at distance 25m from the starting point.

Velocity at t=5s is

v=u+at

or v=10+(−2)×5=0