Question

8. A point charge q is located at (2,3,3) in xyz coordinate. Find the potential
differences between A and BA = (2, 3, 3)B = (-2,3,3)
O q/4nEO
1/16ne0
O 3q/16TED
O None of the above
Other:​

Answer 1

Explanation:

this is your answer.

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Answer 2

The potential difference between A and B is (b) q / 16πε0.

Given: A point charge q is located at (2,3,3) in the XYZ coordinate.

A = (2, 3, 3) and B = (-2,3,3).

To Find: The potential differences between A and B.

Solution:

• The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point or between two particular points.
• The electric potential at a particular point due to another point is given by the formula,

             V = q / 4πε0R                                        .......(1)

where, V = potential difference, ε0 = permittivity of free space, R = distance between two points.

Coming to the numerical we have,

A = (2, 3, 3) and B = (-2,3,3).

So, let the distance between A and B be R,

∴ R = √ ( ( 2 - (-2))² + ( 3 - 3 )² + ( 3 - 3 )² )

      = √16

      = 4 units

Also, the magnitude of charge given is = q

Hence, putting respective values in (1), we get;

           V = q / 4πε0R      

      ⇒  V = q / ( 4πε0 × 4 )

      ⇒  V = q / 16πε0

Hence, the potential difference between A and B is (b) q / 16πε0.

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