Question

8. A quadratic polynomial whose zeroes are 3/5 and -1/2 is

(a) 10x++ x + 3 (b) 10x² + x - 3(e) 10x - x + 3 (d) 10x²-x-3​

Answer 1

Answer:

10x²+6x-5

Step-by-step explanation:

Given sum of zeroes of polynomial is 3/5

-b/a = 3/5

Product of zeroes of polynomial is - 1/2

( since a values are not equal we shall balance them by multiplying the first one by 2 and second one by 5)

So we obtain

-b/a = 6/10 & c/a = - 5/10

Therefore values are as follows

A = 10 b = 6 c = - 5

Now, substituting values in standard form ax²+bx+c = 0

10x²+6x-5 = 0

Answer 2

Answer:

Hope it helps you

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Step-by-step explanation:

Option D is correct