Question

8.A right triangle with sides 6 cm ,8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface area of the solid so formed(pi=3.14) *
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Answer 1

Step-by-step explanation:

AFTER DRAWING THE FIGURE WE COME TO KNOW THAT A CONE IF FORMED WHOSE

l = 10 cm , h = 8 cm , r = 6 cm

Curved surface of the solid (CONE )=πrl

A=πrl=22/7∗10∗6=188.57cm2 

Answer 2

Answer: When a right triangle with sides 6 cm, 8 cm and 10 cm is revolved about the side 8 cm, then solid formed is a cone whose height of a cone, h = 8 cm and radius of a cone, r = 6 cm. Slant height of a cone, l = 10 cm

Volume of a cone = 1/3 πr2h = (1/3) x (22/7) x 6 x 6 x 8

⇒ 6336/21 = 301.7 cm3

and curved surface of the area of cone = πrl

⇒ (22/7) x 6 x 10 = 1320/7 = 188.5 cm2

Hence, the volume and surface area of a cone are 301.7 cm3 and 188.5 cm2, respectively.

Step-by-step explanation: hope it will help you

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