Question

8.A right triangle with sides 6 cm ,8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface area of the solid so formed(pi=3.14) *

Answer 1

Answer:

right triangle with sides 6 cm ,8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface area of the solid so formed(pi=3.14) *

Answer 2

Answer :

⟹ Volume = $301.44\:cm^3$

⟹ Curved surface Area = $188.4\:cm^2$

Explanation :

Since, a right triangle is revolved about the side 8 cm

According to the question :

⇛Height of a cone $(\:h\:)$ = 8 cm

⇛Radius of the cone $(\:r\:)$ = 6 cm

⇛Slant height of a cone $(\:l\:)$ = 10 cm

To find :

➥ Volume of a cone = $1/3\:πr^2h$

= $1/3\:×\:3.14\:×\:6\:×\:6\:×\:8$

= $301.44\:cm^3$

➥ Curved surface area of a cone = $πrl$

= $3.14\:×\:6\:×\:10$

= $188.4\:cm^2$

Refer to the picture ⬆️

♥ So, It's Done ♥ !!