8.A right triangle with sides 6 cm ,8 cm and 10 cm is revolved about the side 8 cm. Find the volume and the curved surface area of the solid so formed(pi=3.14) *
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Step-by-step explanation:
Since, the given right angled triangle is revolved about the side 8 cm, it will form a Cone of radius 6cm and height 8cm.
Volume of a cone = 1/3∏r2h = 1/3×3.14×6×6×8 = 301.44 cm3
Curved Surface area of a cone =∏rl .... (i)
We know that,
l2 = r2 + h2 = 62 + 82 = 36 + 64 = 100
→ l = 10 cm
Substitute the value of l in (i), we get
Curved Surface area of a cone = 3.14 × 6 × 10 = 188.4 cm2
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