Physics, asked by harsh4349, 1 year ago

8) a rubber ball is dropped from a height of 5 m on a plane where the acceleration dure to gravity is not
known on bouncing in rises to a height of 1.8 m. The ball loses its velocity on bouncing by a factor of
a. 16/25
c. 315
d. 9/25

Answers

Answered by Anonymous
1

Explanation:

A ball dropped from a height h on reaching the surface velocity is given by

V1= √2gh1

Let V2 be the velocity with which the ball bounces. It will attain a height h2 given by

V2= √2gh2

V2/V1 = √h2/h1

Given

h1 = 5 m h2 = 1.8 m

V2/V1 = √1.8/5 = √0.36 = 0.6

1 - V2/V1 = V1 - V2 / V1 = 1 - 0.6/1

ANS) 0.4 = 2/5

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