Question

8. A sample of calcium carbonate (CaCO3) has the following percentage composition: Ca= 40%; C = 12%;0=48% If the law of definite proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be (A) 0.016 g B) B 0.16g o 1.6 g (D) 16 g.please give me answer of this question with proper explanation. ​

Answer 1

Explanation:

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Answer 2

Answer:

In 100 g CaCO3, 40 g Ca is present.

In 4 g CaCO3, Let x g Ca be present

4x=10040

⟹x=1.6 g

Explanation:

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