Question

8. A school team won 12 games this year against 8 games won last year. What is the percentage
increase?​

Answer 1

Answer:

50%

Step-by-step explanation:

Let the %increase be x

8+x% of 8 =12

8+x/100*8=12

8+8x/100=12

$\frac{800+8x}{100}=12$

800+8x=1200

8x=1200-800

8x=400

$x= \frac{400}{8}\\ \\x=50$

=50%

Answer 2

50%

Step-by-step explanation:

Increase in number of wins = 12-8 = 4

Percentage increase = 4/8×100% = 50%

Please like and mark answer as brainliest