Question

8.
A shell moving through the air is split into two
fragments of masses m, and m, by its explosion
which adds on energy E to the fragments. The
magnitude of relative velocity between the two
fragments after explosion is
(1)
2E(m. + m2)
(mm2)
(2) V2E (m + m2)
m. m2
(3) V2E
my + /m2
, +
✓m, ma
(4) Zero
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Answer 1

happy dashara and I hope this answer please make as brainlist

Answer 2

Answer:

The correct answer is option (a)

Explanation:

m = reduced mass of the system = $\frac{m_{1}m_{2} }{m_{1}+m_{2} }$

E = $\frac{1}{2}mv^{2}$

$v_{rel} = \sqrt{\frac{2E}{M} }=\sqrt{\frac{2E(m_{1}+m_{2} )}{m_{1}m_{2} } }$

hence option(A) is correct