Question

8. A shopkeeper has 100 litres of oil of one kind, 150 litres of another kind and 250 litres of a
third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity.
What should be the greatest capacity of such a tin?​

Answer 1

Answer:

Step-by-step explanation We need to find the HCF or GCD that is Greatest Common Divisor  

120=2  

3  ×3×5

180=2  

2 ×3  

2 ×5

240=2  

4 ×3×5

GCD=2  

2  ×3×5=60

The greatest capacity = 60 liters

So the merchant needs to fill 60 liters of all types of oils