Question

8. A square board side 10 centimeters, standing vertically, is tilted to the left so that the bottom-right corner is raised 6 centimeters from the ground. 6 cm By what distance is the top-left corner lowered from its original position ? (A) 1 cm (B) 2 cm (C) 3 cm (D) 0.5 cm 5x° 7X° A quadrilateral ABCD has four angles ro 9. vo





PLS SAY THE CORRECT ANSWER THE WRONG ANSWER WILL BE REPORTED ​

Answer 1

Answer:

A square board side 10 centimeters standing vertically.

It tilted to the left so that the bottom right corner is raised 6 centimeters from the ground.

So its one side corner length was x cm from ground

Then x

2

=10

2

−6

2

=100−36=64 cm

x=8cm

Then distance is the top left corner lowered from its original position =10−8=2 cm

Answer 2

A square board side 10 centimeters standing vertically.

It tilted to the left so that the bottom right corner is raised 6 centimeters from the ground.

So its one side corner length was x cm from ground

$\small\bold{Then \: x^2=10^2−6^2=100−36=64 cm}$

x=8cm

Then distance is the top left corner lowered from its original position =10−8=2 cm

Hence, option B.