8. A stone is thrown upwards from the surface of the moon with a velocity of 19.6 m/s.
(a) How much time will it take to attain the maximum height? (b) How high will it go
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Answer:
acceleration on moon = 1/6 the acceleration on earth
= 9.8× 1/6
= 1.62 m/s²
u = 0 m/s
v = 19.6 m/s
t = v - u / a
=19.6 m/s - 0 m/s / 1.62 m/s²
= 12.1 s
time = 12.1 s
s = ut +1/2at²
= 0m + 118.59 m
= 118.59 m
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