Question

8. A sum of money becomes 7/6 of itself in 3 years at
a certain rate of simple interest. In how many
years will the sum become 3 times of iteself
the same rate.​

Answer 1

Answer:

Things to Know :

Simple Interest(SI)   =(PRT)/100          { P is the principal ,t is the time ,r is the rate of interest)

Let the initial principal be =P;

Case 1:

The Amount =7P/6 ;

So the simple interest =P/6;

R = (100*SI)/(P*T);

so,  R= 100P/(P*3*6)  =100/18 %;

Case 2:

Amount =3P

SI =3P-P =2P.

So,    T = (100 *2P*18)/(P* 100)

             =36 years.

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