Question

8. A swimming pool is 30 m long, 20 m broad and 4 m deep. Find the cost of cementing its flore
at the rate of 50 per square metre.
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Answer 1

$\underline{\boxed{\bold{Question}}}$

↠ A swimming pool is 30 m long, 20 m broad and 4 m deep. Find the cost of cementing its floor  at the rate of ₹50/m²

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$\underline{\boxed{\bold{Given}}}$

→ Length of pool = L = 30 m

→ Breadth of pool = B = 20 m

→ Height of pool = H = 4 m

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$\underline{\boxed{\bold{Important \;Formulas}}}$

→ CSA of cuboid = 2H × (L + W)

→ Area of base = L × B

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$\underline{\boxed{\bold{Answer}}}$

Let's Start !

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First let's find lateral surface area of of pool means area of 4 walls.

CSA = 2H × (L + W)

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Substituting values in the given equation,

$:\implies CSA = 2H \times (L + W)$

$:\implies CSA = 2(4) \times (30 + 20)$

$:\implies CSA = 8 \times 50$

$\boxed{:\implies CSA = 400 \;m^{2}}$

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Now let's find area of base of pool

Area of Base = (L × W)

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Substituting values in the given equation,

$:\implies Area\;of\;Base = (L \times W)$

$:\implies Area\;of\;Base = (30 \times 20)$

$\boxed{:\implies Area\;of\;Base = 600 \;m^2}$

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So total area to be cemented = CSA + Area of base

                                                   = (400 + 600) m²

                                                   = 1000 m²

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$\boxed{\boxed{\bold{\therefore Total\;Area\;to\;be\;cemented = 1000\;m^{2} }}}$

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Cost of cementing = Rate × Total Area

                                = 50 × 1000

                                = ₹50,000

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$\boxed{\boxed{\bold{\therefore Total\;cost\;of\;cementing = Rs.\;50,000 }}}$

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Hope this helps u.../

【Brainly Advisor】

Answer 2

Answer:

thanks for free points ❤️❤️