Question

8. A tank of 425 litres capacity has been filled with water through two pipes, the first pipe having been opened five hours longer than the second. If the first pipe were open as long as the second, and the second pipe was open as long as the first pipe was open, then the first pipe would deliver half the amount of water delivered by the second pipe; if the two pipes were open simultaneously, the tank would be filled up in 17 hours. How long was the second pipe open? (a) 10 hours (b) 12 hours (c) 15 hours (d) 18 hours

SOLUTION: So work = 425 and time = 17

Efficiency=w/t

= 425/17

= 25

So efficiency of first and second pipe will

be 25

According to question first pipe is opened 5 hours longer than the second, so it will be x - 5,x

So x-5+x=25

2x = 30

x = 15

Now first pipe will be 15-5 = 10 hours and

second pipe will be for 15 hours...

Now my question is that why have we taken x-5 for the first pipe when it's taking 5 hours longer than the second....
GENUINE ANSWERS PLEASE​

Answer 1

Step-by-step explanation:

According to question first pipe is opened 5 hours longer than the second, so it will be x - 5,x

So x-5+x=25

2x = 30

x = 15

Now first pipe will be 15-5 = 10 hours and

second pipe will be for 15 hours...

Now my question is that why have we taken x-5 for the first pipe when it's taking 5 hours longer

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