Question

8.
A train leaves Kanniyakumari for Warany on Tuesday at 10:30 am. If Warangal is 1586 km from Kanniy
when will it reach there if its speed is 39 k hr?
Arun drives his car at 60 km/hr. How much i nce will he cover in 2 hours 15 seconds?
9.
Soren​

Answer 1

Answer:

Time taken by the train to reach Warangal =

39

1586

=40 hr40 min

If the train starts on Tuesday at 10:30 am, it will reach Warangal on Thursday 3 : 10 am

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Answer 2

Answer:

$time \: = \frac{}{speed} distance \:$

time = 1586 /39

= 40.6 hours hence it will reach at 2:30 am on Thursday

time = 2 hours 15 minutes

= 2 + 15/60

= 2+0.25

2.25 h

distance = 60× 2.25

= 135 km