Question

8. A two digit number has ‘a' and 'B'as units and tens digit respectively. Number is equal
to 10b + a and the number obtained by interchanging the order of the digits is 10a + b.​

Answer 1

ANSWER

Let the units digit be x, so tens digit = 2x+2

Original no. = 10(2x+2)+x=21x+20

Reversed no. = 10x+2x+2=12x+2

Sum of digits = 2x+2+x=3x+2

3(3x+2)+5=12x+2

9x+6+5=12x+2

3x=9

x=3

∴ Tens digit = 8

The number is = 83