8. A two-digit number is 4 more than 6 times the sum of its digits. If 18 is subtracted
from the number, the digits are reversed. Find the number
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Answer:
64
Step-by-step explanation:
Let x= ones digit and y=tens digit
According to the question ,
∴x+10y=6(x+y)+4⇒10y=6x+6y+4−x⇒4y=5x+4
And , from if 18 is substracted from the number , the digits are reversed ,
∴x+10y−18=y+10x⇒10y−18=y+9x⇒9y−18=9x⇒y−2=x
Substitute x value into :
4y=5x+44y=5(y−2)+44y=5y−6y=6
Substitute y into :
∴y−2=x⇒6−2=x⇒4=x
∴ The number is 64.
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