Question

8. A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits
are reversed. Find the number.
(CBSE 2001C)​

Answer 1

Answer:

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so here we go

Step-by-step explanation:

let the two digit number be 10x+y

so then reversed number =10y+x

so here let digit at tens place for original number be x and that of in it be y

so according to first given condition

10x+y=4(x+y)

10x+y=4x+4y

ie 6x=3y

ie y=2x (1)

so according to second condition

10x+y18=10y+x

ie 9x=9y-18

ie 9x-9y=-18

so x-y=-2 (2)

substitute value of y from (1) in (2)

we get x-2x=-2

ie -x=-2

ie x=2

so substitute value of x in (2)

you get y=4

so our assumed two digit number was

10x+y

=(10×2)+4

=20+4

24

hence required two digit number is 24

u can surely bet on my answer

u can verify the answer by substituting values of x and y in formed equations