8. A two-digit number is 4 times the sum of its digits. If 18 is added to the number, the digits
are reversed. Find the number.
(CBSE 2001C)
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Answer:
hey here is your answer
pls mark it as brainliest
so here we go
Step-by-step explanation:
let the two digit number be 10x+y
so then reversed number =10y+x
so here let digit at tens place for original number be x and that of in it be y
so according to first given condition
10x+y=4(x+y)
10x+y=4x+4y
ie 6x=3y
ie y=2x (1)
so according to second condition
10x+y18=10y+x
ie 9x=9y-18
ie 9x-9y=-18
so x-y=-2 (2)
substitute value of y from (1) in (2)
we get x-2x=-2
ie -x=-2
ie x=2
so substitute value of x in (2)
you get y=4
so our assumed two digit number was
10x+y
=(10×2)+4
=20+4
24
hence required two digit number is 24
u can surely bet on my answer
u can verify the answer by substituting values of x and y in formed equations
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