8.
A vessel of irregular shape has a volume 'V'.
It is first evacuated amd coupled with a vessel
of 4L capacity at 35°C and 10 atm pressure.
If the final pressure in both the vessels is 3atm,
calculate the volume V.
1) 9.3 L 2) 8 L 3) 6L 4) 8.3 L
Answers
Hi,
Answer:
The volume “V” of the irregular shape vessel is 9.8 L.
Explanation:
Given data:
The volume of the irregular shape vessel is “V”
The other vessel has a volume Vo = 4 L at pressure, Po =10 atm and temperature, T = 35°C
The final pressure of the vessels after coupling them = 3 atm
To find: Volume “V”
Since pressure in the other vessel is reduced from 10 atm to 3 atm after being coupled with the irregular vessel. Therefore, change in the pressure in the other vessel = 10 – 3 = 7 atm
Using the Ideal Gas Law,
PV = nRT
Moles of substance in the irregular vessel after coupling = PV / RT = 3 * V / RT ….(i)
Moles of substance in the other vessel after coupling = (change in pressure) * Vo / RT = 7 * 4 / RT ….(ii)
Equating (i) & (ii), we get
3 * V / RT = 7 * 4 / RT
Or, 3 * V = 7 * 4
Or, V = 9.8 L
Hope this helps!!!!
Answer:
option number 1
Explanation:
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