Question

8.
A wire is in the shape of a square of side 20 cm. If the wire is bent into a rectangle
of length 24 cm, find its breadth
with statements plllllllllĺllllllllllllllease ​

Answer 1

Step-by-step explanation:

answer is 16 and 16 cm on both sides.

explanation

the perimeter of a square will be 20×4(sides)=80 cm.

if the length of the rectangle is 24 cm . then 24×2=48 cm ,will be the total length of the rectangle on both sides.

so, 80-48=32

so, 32 will be the breadth of the rectangle on both the sides.

16 cm on one side

Answer 2

Question:-

A wire is in the shape of a square of side 20 cm. If the wire is bent into a rectangle of length 24 cm, find its breadth

Answer:-

• The breadth of rectangle is 16 cm.

To find:-

• Breadth of rectangle

Solution:-

• Side of square = 20 cm

We have to find the perimeter of square.

As we know,

$\large{ \boxed{ \mathfrak{perimeter = 4 \times side}}}$

Put the values in the formula,

$\large{ \rm: \implies \: \: \: \: \: \: \: \: perimeter = 4 \times 20}$

$\large{ \rm: \implies \: \: \: \: \: \: \: \: perimeter = 80}$

• The perimeter of square is 80 cm

As we bent the same wire into a rectangle.

Thus,

• Perimeter of square = perimeter of rectangle

As we know,

$\large{ \boxed{ \mathfrak{perimeter = 2(l + b)}}}$

Where,

• l = length of rectangle = 24 cm
• b = breadth of rectangle

According to question,

$\large{ \rm: \implies \: \: \: \: \: \: \: \: 2(24 + b) = 80}$

$\large{ \rm: \implies \: \: \: \: \: \: \: \: 24 + b = \frac{80}{2} }$

$\large{ \rm: \implies \: \: \: \: \: \: \: \: 24 + b = 40}$

$\large{ \rm: \implies \: \: \: \: \: \: \: \: b = 40 - 24}$

$\large{ \rm: \implies \: \: \: \: \: \: \: \: b = 16}$

Hence,

The breadth of rectangle is 16 cm.