Question

8. A wire of thickness 2mm of
length 10cm is having resistivity
16 n 12 m, is expanded twice its
length. Find the resistance of
the new wire.​

Answer 1

Answer:

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Explanation:

Given,

l=0.1m=1000mm

d=0.2mm∴radius(r)=

2

0.2

=0.1mm

R=10Ω

To find,

Resistivity(ρ)

ρ=R

l

A

where,

R= Resistance

l= Length of wire

A= Cross sectional area of wire

Cross sectional area of cylinder (A)=Πr

2

⇒A=π×(0.1)

2

⇒A=0.0314mm

2

∴ρ=10(

1000

0.0341

)

⇒ρ=0.000314Ω−mm

⇒ρ≃3.14×10

−7

Ω−m

So, the resistivity of the material is equal to 3.14×10

−7

Ω−m

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