8. AABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of AABC. What will be the height from C to AB i.e.,
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In triangle ABC, AD = 6 cm and BC = 9 cm
Area of triangle ABC = 1/2 × Base × Height
= 1/2 × BC × AD
= 1/2 × 9 cm × 6 cm
= 27 cm2
Now, Area of triangle ABC = 1/2 × AB × CE
27 cm2 = 1/2 × 7.5 cm × CE
CE = (2 × 27 cm2) / 7.5 cm
CE = 54 cm2 / 7.5 cm
CE = 7.2 cm
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