Question

8. ABC is an equilateral triangle. Pis a point on AB and Q was a point on AB produced. Prove at
$cp < ab \: and \: cq > ab$


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Answer 1

Answer:

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ] [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c [common]

and BC=BC [common]

∴ΔBCP≃ΔBCQ [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles

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