Math, asked by rocky4531, 11 months ago


8.ABCD is a parallelogram.CE is the height from C to AB and CF is the height from C to
ADIT AB=15cm and CE=8cm, Find i the area of parallelogram ABCD ii)CF,if AD=12cm.​

Answers

Answered by amitnrw
7

Area of a parallelogram = 120 cm² &  CF = 10  cm if AB=15cm and CE=8cm & AD = 12 cm

Step-by-step explanation:

ABCD is a parallelogram.CE is the height from C to AB

=> Area of a parallelogram = AB * CE   ( Base * altitude)

AB = 15 cm  CE = 8 cm

= 15 * 8

= 120 cm²

Area of a parallelogram = AD * CF

AD = 12 cm

= 12 * CF  

12 * CF = 120

=> CF = 10  cm

Area of a parallelogram = 120 cm²

CF = 10  cm

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Answered by isyllus
3

(i) The area of parallelogram ABCD is 120 cm²

(ii) CF = 10 cm

Step-by-step explanation:

ABCD is a parallelogram.

Please see attachment for figure.

CE is the height from C to AB.

CE is perpendicular to AB.

where, CE = 8 cm and AB = 15 cm

Area of parallelogram = Product of side to their corresponding height

Area of parallelogram = AB × CE

                                     = 15 × 8

                                    = 120 cm²

Hence, the area of parallelogram ABCD is 120 cm²

CF is the height from C to AD.

CF is perpendicular to AD.

Let length of CF is x cm

where, CF = x cm and AD = 12 cm

Area of parallelogram = AD × CF

                              120 = 12 × x

                                 x = 10 cm

Hence, the length of CD is 10 cm

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