8.ABCD is a parallelogram.CE is the height from C to AB and CF is the height from C to
ADIT AB=15cm and CE=8cm, Find i the area of parallelogram ABCD ii)CF,if AD=12cm.
Answers
Area of a parallelogram = 120 cm² & CF = 10 cm if AB=15cm and CE=8cm & AD = 12 cm
Step-by-step explanation:
ABCD is a parallelogram.CE is the height from C to AB
=> Area of a parallelogram = AB * CE ( Base * altitude)
AB = 15 cm CE = 8 cm
= 15 * 8
= 120 cm²
Area of a parallelogram = AD * CF
AD = 12 cm
= 12 * CF
12 * CF = 120
=> CF = 10 cm
Area of a parallelogram = 120 cm²
CF = 10 cm
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(i) The area of parallelogram ABCD is 120 cm²
(ii) CF = 10 cm
Step-by-step explanation:
ABCD is a parallelogram.
Please see attachment for figure.
CE is the height from C to AB.
CE is perpendicular to AB.
where, CE = 8 cm and AB = 15 cm
Area of parallelogram = Product of side to their corresponding height
Area of parallelogram = AB × CE
= 15 × 8
= 120 cm²
Hence, the area of parallelogram ABCD is 120 cm²
CF is the height from C to AD.
CF is perpendicular to AD.
Let length of CF is x cm
where, CF = x cm and AD = 12 cm
Area of parallelogram = AD × CF
120 = 12 × x
x = 10 cm
Hence, the length of CD is 10 cm
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