Question

8. ABCD is a quadrilateral.AO and BO are the angle bisectors of angle A and B which meet at O. If angle C =70° angle D =50° find angle AOB​

Answer 1

Answer:

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Step-by-step explanation:

Angle A + Angle B + Angle C + Angle D= 360 degrees

Let Angle A and Angle B be 'x'

So, x+x+70+50=360

2x+120=360

2x=360-120

2x=240

x=120

Therefore, Angle A is 120

Angle B is 120

Angle C is 70

Angle D is 50

Angle AO and Angle BO bisects Angle Aa and Angle B

So, Angle A = 120\2 = 60

Angle B = 120\2 = 60

In a triangle,

Angle AOB + Angle OAB + Angle OBA = 180 degrees

Angle AOB + 60 + 60 = 180

Angle AOB + 120 = 180

Angle AOB = 180-120

Angle AOB = 60

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