Question

8. Aboy walking at a speed of 10 km/h reaches his school 15 minutes late Next time he increases
his speed by 2 km/h, but still he is late by 5 minutes. Find the distance of his school from his​

Answer 1

Answer:

Step-by-step explanation:

Let d be the distance of school from house.

Difference in time taken = 15 -5 = 10 min = 10/60 = 1/6 hr.

We know that Speed = Distance/time

=> d/10 - d/12 = 1/6

=> 6d-5d/60 = 1/6

=> d= 60/6 = 10 km.

Thus distance of his school from house = 10 km.

Answer 2

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Distance of the school from his home is 10 km.