Math, asked by vijayuc99, 3 months ago

8) Akhil and Naman contested the election of panchayat committee from their village. Akhil
scored 11,484 votes which was 44% of the total vote. Naman scored 26% of the votes.
Calculate :
(a) The number of votes cast in the village
(b )The number of voters who did not vote for either Akhil or Naman.

Answers

Answered by xXMarziyaXx
3

Answer

Total votes casted= 26100

Total voters who did not vote either to Ramesh and Satish is 7830

Step-by-step explanation:

Let X be the total voters.

Ramesh scored 44 % of X = 11484

44 X /100 = 11484

X = 11484 × 100/44

X = 26100.

Total no. of votes casted in the village is 26100

Now, Satish scored 26 % of 26100

26 × 26100/100 = 678600/ 100 = 6786 voters.

Total votes casted to Satish and Ramesh= 11484+ 6786= 18270

Total votes casted= 26100

voters who did not vote either to Ramesh and satish= 26100-18270= 7830

Total voters who did not vote either to Ramesh and Satish is 7830

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Answered by UniqueBabe
6

 \huge \pink {answeR}

Total votes casted= 26100

Total voters who did not vote either to Ramesh and Satish is 7830

Step-by-step explanation:

Let X be the total voters.

Ramesh scored 44 % of X = 11484

44 X /100 = 11484

X = 11484 × 100/44

X = 26100.

Total no. of votes casted in the village is 26100

Now, Satish scored 26 % of 26100

26 × 26100/100 = 678600/ 100 = 6786 voters.

Total votes casted to Satish and Ramesh= 11484+ 6786= 18270

Total votes casted= 26100

voters who did not vote either to Ramesh and satish= 26100-18270= 7830

Total voters who did not vote either to Ramesh and Satish is 7830

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