Question

8.An air bubble of radius 0.2 mm is situated just below the water surface. Calculate the
gauge pressure. Surface tension of water = 7.2 *10
-2

Answer 1

Answer:

Explanation:

Surface tension of water

Tw=7.2*10^-2 N/m

Atomspheric pressure

P atm =1.013*10^5 N/m

Radius of bubble R=0.1 mm

= 0.1*10^-3m = 1*10^-4m

Pressure=P atm +2T/R

P= 1.013*10^5+2(7.2*10^-2)/1*10^-4

P= 1.013*10^5+14.4*10^-2*10^4

P= 1.013*10^5+144

P= 1.014*10^5+0.0144*10^5

P=1.0144*10^5N/m^2