8. An elevator descends into a mine shaft at the rate of 6 m/min. If the descend
starts from 10 m above the ground level, how long will it take to reach the shaft
350 m below the ground level?
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Answer:
the distance the elevator should travel = 350 +10 = 360m
Speed of the elevator = 6m/min
time taken by the elevator to reach the shaft = distance/speed = 360/6 = 60min
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