Question

8.An object is placed perpendicular to the principal axis of a diverging lens of power of lens (10)/(3)D .find the position of an image when the object is at a distance 20cm from the lens.

Answer 1

Given:u=−10cm f=20cm (convex lens)

To find: v and image's nature.

Solution: From lens formula

v

1

−

u

1

=

f

1

v

1

+

10

1

=

20

1

v

1

=

20

−1

v=−20cm

And magnification =

u

v

=2

Hence image formed is virtual, erect and magnified two times.

Answer 2

Answer:

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Explanation:

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